Q:
麻烦问下视图跳转视图时这个url的属性值由哪几部分组成呀,我看咱们论坛写的url一直报错
var url = getContextPath()+"/portal/dynaform/view/displayViewWithPermission.action?_resourceid="+resouce_id+"&_viewid="+view_id+"&clearTemp=true&application="+application_id+"&cusname="+val+"&_docid="+doc_id;
var url =getContextPath()+"/portal/good/dynaform/view/displayViewWithPermission.action?_resourceid="+resouce_id+"&_viewid="+view_id+"&clearTemp=true&application="+application_id+"&cusname="+val+"&_docid="+doc_id;
上面的代码是论坛上看到的,下面这个是我自己改的
A:
(function(){
var request = $WEB.getParamsTable().getHttpRequest();//获取当前request
var url1="http://"+request.getServerName()+":"+request.getServerPort();
var url = url1+getContextPath()+"/portal/vue/html/view.html?&viewId=n3RPxv8mWq8i8PpPkle&clearTemp=true&application="+getApplication(); //viewid:要跳转的视图id.
return url;
})()