本帖最后由 irene 于 2012-8-3 17:00 编辑
在表单的源代码中, 自己写了一个 function , ajax 请求后台, 页面提示找不到请求 ~
代码如下 :- function insertUnit(){
- alert("执行 insert 操作");
- var receiptUnit = document.getElementById('receiptUnit').value;
- var bankOfDeposit = document.getElementById('bankOfDeposit').value;
- var receiptBankCode = document.getElementById('receiptBankCode').value;
- var depositBankAddress = document.getElementById('depositBankAddress').value;
- var uuId = document.getElementById('uuId').value;
- $.ajax({
- type:'post',
- url:'unitAdd.mvc',
- data:'supplierName='+receiptUnit+'&bankCardNo='+receiptBankCode+'&bankOfDeposit='+bankOfDeposit+'&bankAddress='+depositBankAddress+'&id='+uuId,
- success:function(data){
- alert(data);
- }
- });
- }
复制代码 异常:
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