关于函数queryBySQL问题

函数代码如下：
function getExpertsPercentByPass(parentid){
var sql="select cast(cast((select count(*)from tlk_f_zjopinion where item_IsPassReview ='通过' or item_IsPassReview='调整后通过' and parent='"+parentid+"')*1.0*100/count(*) as decimal(10,2)) as varchar(50)) +'%' as item_percent,'1' as domainid,'2' as id from tlk_f_zjopinion where (cast(item_nowuser as nvarchar) is not null or cast(item_nowuser as nvarchar) !='')";
        println("===sql==="+sql);
        var data =queryBySQL(sql);
println("====data=="+data );
        var count=0;
        if(data !=null){
        for(var iter =data.iterator();iter.hasNext();){
                var doc=iter.next();
                count =doc.getItemValueAsString("percent");
        }
        }
        return  count;
}

打印sql语句有数据，但data为空，什么原因呢？（注sqlserver数据库）

您好，您获取domainid时不要用'1' as domainid，可修改成'"+getDomainid()+"' domainid

好的。问题已解决。谢谢！

感谢您的回复