关于流程通知

var  from = obpm@totalpaperservicces.com;
var to = ??  //to request submitter
var host = mail.totalpaperservics.com;
var user = from;
var emailpassword = 123456;
var bbc = null;
var validate = true;
var subject = “Approved notice”;
var body = “ You request was approved”;
sendMail(from, to, subject, body, host, user, emailpassword, bbc, validate);

请帮忙看下。谢谢

var  from = obpm@totalpaperservicces.com;
var to = ??  //to request submitter
var host = mail.totalpaperservics.com;
var user = from;
var emailpassword = 123456;
var bbc = null;
var validate = true;
var subject = “Approved notice”;
var body = “ You request was approved”;
sendMail(from, to, subject, body, host, user, emailpassword, bbc, validate);

您好，您的代码对应修改一下，如：
var doc = getCurrentDocument();
var to=doc.getAuthor().getEmail();//获取作者的邮件
var  from ="obpm@totalpaperservicces.com";
var subject="测试邮件发送主题";
var content="测试内容";
var host="填写邮件服务器地址";
var user="填写邮件服务器用户名";
var pwd="邮件密码";
var bbc="抄送地址";
var validate=true;
sendMail(from,to,subject,content,host,user,pwd,bbc,validate);

from：发送人地址；(**@teemlink.com)
to：接收人地址；(******@qq.com)
subject：主题；
body：内容；
host：邮件服务器地址；(teemlink.com)
user：邮件服务器用户名；(**)
password：密码；
bbc：秘密抄送地址；(*********@163.com)
validate：是否校验；
发送邮件给指定用户。
示例：
实现sendMail(from, to, subject, body, host, user, password, bbc,  validate)函数的应用，发送邮件给指定用户

万分感谢！

body中怎样包含link？  如http://obpm.totalpaperservices.com:8080/obpm
var body= “ 如http://obpm.totalpaperservices.com:8080/obpm ”   对吗？

这个问题客户已在另一个帖子上解决了：http://teemlink.com/bbs/viewthre ... %26amp%3Btypeid%3D2

故关闭该帖子