select '11e2-1f4d-088fc9fa-b7a9-316e368ea088' as id, '11e1-8dbd-ab7d5b48-a68d-3f24143e1fe8' as domainid, '11e1-8db9-aa164da3-a68d-3f24143e1fe8' as applicationid,'11e2-1f4a-0b55f649-b7a9-316e368ea088' as formid,ITEM_票据起始号,ITEM_票据结束号 from
如上是这样从别的表中查出来的数据,然后ID都是一样的请问这样怎么解决选中行的字段值