创建视图时数据来源选择sql, sql代码如下:
var sql="select a.Item_level level,b.ITEM_CONTACTS contacts from tlk_mc_info a left join tlk_mc_contacts b on b.parent= a.id where 1=1"
sql;
技术联系,加上两个字段ID和domainid后解决:
var sql="select a.id,a.domainid,a.Item_level level,b.ITEM_CONTACTS contacts from tlk_mc_info a left join tlk_mc_contacts b on b.parent= a.id where 1=1"
sql;